| ⇦ |
| ⇨ |
The phase difference between the flux linked with a coil rotating in a uniform magnetic field and induced emf produced in it is
Options
(a) π/2
(b) π/3
(c) (-π/6)
(d) π
Correct Answer:
π/2
Explanation:
The flux ɸ = B.A = |B| |A| cos θ
Also, induced emf, ε = – (dɸ / dt) = (d |B| |A| cos θ) / dt
= – |B| |A| [d cos θ / dt] = |B| |A| sin θ. ω
ε = BA ω cos [θ – (π / 2)]
Related Questions: - A 2 kg mass starts from rest on an inclined smooth surface with inclination
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- A body travelling along a straight line traversed one-third of the total distance
- Light is emitted when
- A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 2 kg mass starts from rest on an inclined smooth surface with inclination
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- A body travelling along a straight line traversed one-third of the total distance
- Light is emitted when
- A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply