The phase difference between the flux linked with a coil rotating in a uniform

⇦

⇨

The phase difference between the flux linked with a coil rotating in a uniform magnetic field and induced emf produced in it is

Options

(a) π/2
(b) π/3
(c) (-π/6)
(d) π

Correct Answer:

π/2

Explanation:

The flux ɸ = B.A = |B| |A| cos θ

Also, induced emf, ε = – (dɸ / dt) = (d |B| |A| cos θ) / dt

= – |B| |A| [d cos θ / dt] = |B| |A| sin θ. ω

ε = BA ω cos [θ – (π / 2)]

Related Questions:

1. In Bohr model of hydrogen atom, the force on the electron depends on the principal
2. Heat is flowing through a rod of length 50 cm and area of cross-section 5 cm².
3. A geostationary satellite is orbiting the earth at a height of 5R above that surface
4. A speeding motorcyclist sees traffic jam ahead him. He slows down to 36 km per hour
5. The de-Broglie wavelength of an electron is the same as that of a 50 KeV X-ray photon.

Topics: Electromagnetic Induction (76)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends