⇦ | ![]() | ⇨ |
The periodic waves of intensities I₁ and I₂ pass through a region at the same time in the same direction. The sum of the maximum and minimum intensities is:
Options
(a) I₁ + I₂
(b) (√I₁ + √I₂)²
(c) (√I₁ – √I₂)²
(d) 2 (I₁ + I₂)
Correct Answer:
2 (I₁ + I₂)
Explanation:
The resultant intensity of two periodic waves at a point is given by
I = I₁ + I₂ + 2 √I₁I₂ . cos ?.
Resultant intensity is max. if cos ? = -1
i.e Iₘₐₓ = I₁ + I₂ + 2 √I₁I₂
Resultant intensity is min. if cos ? = +1
i.e, Iₘᵢₙ = I₁ + I₂ – 2 √I₁I₂
Therefore, the sum of the max. and min. intensities is Iₘₐₓ + Iₘᵢₙ
= I₁ + I₂ + 2 √I₁I₂ + I₁ + I₂ – 2 √I₁I₂
= 2 (I₁ + I₂)
Related Questions:
- In India, electricity is supplied for domestic use at 200V. It is supplied at 110 V
- When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles
- The Davisson- Germer experiment is the direct evidence of
- If particles are moving with same velocity, then maximum de Broglie wavelength will
- Length of a string tied to two rigid supports is 40 cm. Maximum length
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply