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The percentage weight of Zn in white vitriol [ZnSO₄ 7H₂O] is approximately equal to Zn=65, S=32, O=16 and H=1)
Options
(a) 33.65%
(b) 32.56%
(c) 23.65%
(d) 22.65%
Correct Answer:
22.65%
Explanation:
Mol. Wt of ZnSO₄ 7H₂O = 65 + 32 + (4 x 16) + 7 (2 x 1 +16)=287
% Mass of Zinc = 65/287 x 100 = 22.65%
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Question Type: Memory
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Difficulty Level: Easy
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Topics: Basic Concepts of Chemistry
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Subject: Chemistry
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a spontaneous process, entropy always
- At 27⁰C latent heat of fusion of a compound is 2930 J/mol. Entropy change is
- A mixture of champhor and benzoic acid can be separated by
- 300 mL of a gas at 27⁰C is cooled to -3⁰C at constant pressure
- Metallic sodium can be stored in
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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