| ⇦ | 
| ⇨ |
The percentage weight of Zn in white vitriol [ZnSO₄ 7H₂O] is approximately equal to Zn=65, S=32, O=16 and H=1)
Options
(a) 33.65%
(b) 32.56%
(c) 23.65%
(d) 22.65%
Correct Answer:
22.65%
Explanation:
Mol. Wt of ZnSO₄ 7H₂O = 65 + 32 + (4 x 16) + 7 (2 x 1 +16)=287
% Mass of Zinc = 65/287 x 100 = 22.65%
Related Questions: - The molecular weight of a gas is 45. Its density at STP is
- As the nuclear charge increases from neon to calcium the orbital energy
- Diethyl ether is isomeric with
- When acetone reacts with bleaching powder, the compound formed is
- In the formation of [Ni(CN)₄]²⁻, the type of hybridisation involved is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The molecular weight of a gas is 45. Its density at STP is
- As the nuclear charge increases from neon to calcium the orbital energy
- Diethyl ether is isomeric with
- When acetone reacts with bleaching powder, the compound formed is
- In the formation of [Ni(CN)₄]²⁻, the type of hybridisation involved is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply