| ⇦ | 
| ⇨ |
The percentage weight of Zn in white vitriol [ZnSO₄ 7H₂O] is approximately equal to Zn=65, S=32, O=16 and H=1)
Options
(a) 33.65%
(b) 32.56%
(c) 23.65%
(d) 22.65%
Correct Answer:
22.65%
Explanation:
Mol. Wt of ZnSO₄ 7H₂O = 65 + 32 + (4 x 16) + 7 (2 x 1 +16)=287
% Mass of Zinc = 65/287 x 100 = 22.65%
Related Questions: - Artificial sweetner which is stable under cold conditions only is
- Which of these is a hypnotic
- Arrange the following in increasing order of acidity H₃PO₄ , H₂CO₃ , HCl , HI
- A gas can be liquefied
- Which of the following compounds possesses the C-H bond with the lowest bond dissociation
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Artificial sweetner which is stable under cold conditions only is
- Which of these is a hypnotic
- Arrange the following in increasing order of acidity H₃PO₄ , H₂CO₃ , HCl , HI
- A gas can be liquefied
- Which of the following compounds possesses the C-H bond with the lowest bond dissociation
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply