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The pair of quantities having same dimensions is
Options
(a) Young’s modulus and energy
(b) impulse and surface tension
(c) angular momentum and work
(d) work and torque
Correct Answer:
work and torque
Explanation:
Work = Force x displacement
Torque = Force x force arm
= mass x acceleration x length
= [M] x [LT⁻²] x [L] = ML²T⁻²
Related Questions: - Which of the following is true for elastic potential energy density?
- A particle with charge q is moving along a circle of radius R with unoform speed v.
- A particle of mass m is projected with a velocity v making an angle of 45°
- The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm².
- The electric potential V at any point (x,y,z) all in meters in space is given by
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is true for elastic potential energy density?
- A particle with charge q is moving along a circle of radius R with unoform speed v.
- A particle of mass m is projected with a velocity v making an angle of 45°
- The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm².
- The electric potential V at any point (x,y,z) all in meters in space is given by
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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