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The pair of quantities having same dimensions is
Options
(a) Young’s modulus and energy
(b) impulse and surface tension
(c) angular momentum and work
(d) work and torque
Correct Answer:
work and torque
Explanation:
Work = Force x displacement
Torque = Force x force arm
= mass x acceleration x length
= [M] x [LT⁻²] x [L] = ML²T⁻²
Related Questions: - The sum of the magnitudes of two forces acting at a point is 16 N
- Two point objects of masses 1.5 g and 2.5 g respectively are at a distance of 16 cm
- A 220 volts input is supplied to a transformer. The output circuit draws
- Energy of photon whose frequency is 10¹² MHz will be
- The ratio of the dimensions of planck’s constant and that of the moment of inertia is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The sum of the magnitudes of two forces acting at a point is 16 N
- Two point objects of masses 1.5 g and 2.5 g respectively are at a distance of 16 cm
- A 220 volts input is supplied to a transformer. The output circuit draws
- Energy of photon whose frequency is 10¹² MHz will be
- The ratio of the dimensions of planck’s constant and that of the moment of inertia is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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