⇦ | ⇨ |
The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻ follow the order
Options
(a) S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
(b) SO₃²⁻ < S₂O₄²⁻ < S₂O₆²⁻
(c) S₂O₄²⁻ < S₂O₆²⁻ < SO₃²⁻
(d) S₂O₆²⁻ < S₂O₄²⁻ < SO₃²⁻
Correct Answer:
S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The bond angle of sp² – hybrid orbital is
- As we go from left to right in a period of the periodic table, gram atomic volume
- On treating a mixture of two alkyl halides with sodium metal in dry ether,
- If uncertainty in position and momentum are equal, then uncertainty in velocity
- If 10 cm³ solution of H₂O₂ ,on decomposition gives 150 cm³ of O₂
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The bond angle of sp² – hybrid orbital is
- As we go from left to right in a period of the periodic table, gram atomic volume
- On treating a mixture of two alkyl halides with sodium metal in dry ether,
- If uncertainty in position and momentum are equal, then uncertainty in velocity
- If 10 cm³ solution of H₂O₂ ,on decomposition gives 150 cm³ of O₂
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply