| ⇦ | 
| ⇨ |
The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻ follow the order
Options
(a) S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
(b) SO₃²⁻ < S₂O₄²⁻ < S₂O₆²⁻
(c) S₂O₄²⁻ < S₂O₆²⁻ < SO₃²⁻
(d) S₂O₆²⁻ < S₂O₄²⁻ < SO₃²⁻
Correct Answer:
S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following can act as an oxidising as well as reducing agent
- The reaction of which of the following compounds would yield secondary amine
- What is formed when nitrobenzene is reduced using zinc and alkali
- 2-phenylethylbromide when heated with NaOEt, elimination takes place.
- If 200 mL of gas at 27°C is cooled to 7°C at constant pressure, its final volume will be
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following can act as an oxidising as well as reducing agent
- The reaction of which of the following compounds would yield secondary amine
- What is formed when nitrobenzene is reduced using zinc and alkali
- 2-phenylethylbromide when heated with NaOEt, elimination takes place.
- If 200 mL of gas at 27°C is cooled to 7°C at constant pressure, its final volume will be
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply