The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻

⇦

⇨

The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻ follow the order

Options

(a) S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
(b) SO₃²⁻ < S₂O₄²⁻ < S₂O₆²⁻
(c) S₂O₄²⁻ < S₂O₆²⁻ < SO₃²⁻
(d) S₂O₆²⁻ < S₂O₄²⁻ < SO₃²⁻

Correct Answer:

S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

1. Which of the following pairs of ions are isoelectronic and isostructural
2. In the compounds KMnO₄ and K₂Cr₂O₇, the highest oxidation state is of the element
3. For a first order reaction, the half -life period is independent of
4. The reduction of benzoyl chloride with H₂/Pd BaSO₄ gives
5. If 900 J/g of heat is exchanged at boiling point of water, then what is increase

Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends