| ⇦ | 
| ⇨ |
The oxidation states of sulphur in the anions : SO₃²⁻,S₂O₄²⁻ and S₂O₆²⁻ follow the order
Options
(a) S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
(b) SO₃²⁻ < S₂O₄²⁻ < S₂O₆²⁻
(c) S₂O₄²⁻ < S₂O₆²⁻ < SO₃²⁻
(d) S₂O₆²⁻ < S₂O₄²⁻ < SO₃²⁻
Correct Answer:
S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Benzaldehyde condenses with N,N-dimethylaniline in presence of anhydrous ZnCl₂
- The banana bond in diborane is constituted by
- The nucleic acid base having two possible binding sites is
- What is the mole fraction of the solute in a 1.00 m aqueous solution?
- Benzene hexachloride is an
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Benzaldehyde condenses with N,N-dimethylaniline in presence of anhydrous ZnCl₂
- The banana bond in diborane is constituted by
- The nucleic acid base having two possible binding sites is
- What is the mole fraction of the solute in a 1.00 m aqueous solution?
- Benzene hexachloride is an
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply