| ⇦ |
| ⇨ |
The orbital angular momentum of a p-electron is given as :
Options
(a) h/(√2π)
(b) √3 x (h/2π)
(c) √(3/2) x h/π
(d) √6 x h/2π
Correct Answer:
h/(√2π)
Explanation:
Orbital Angular Momentum = h/(2π) x √(l(l+1)). For p orbital, l=1. so => h/(2π) x √2 =? h/(√2π)
Related Questions: - What is the approximate percentage of H₂O₂ in a sample labelled as 10 V?
- Calcium is obtained by the
- Tollen’s test can be used to distinguish
- The radius of hydrogen atom in the ground state is 0.53 Å. The radius
- One would expect proton to have very large
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the approximate percentage of H₂O₂ in a sample labelled as 10 V?
- Calcium is obtained by the
- Tollen’s test can be used to distinguish
- The radius of hydrogen atom in the ground state is 0.53 Å. The radius
- One would expect proton to have very large
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply