| ⇦ | 
| ⇨ |
The orbital angular momentum of a p-electron is given as :
Options
(a) h/(√2π)
(b) √3 x (h/2π)
(c) √(3/2) x h/π
(d) √6 x h/2π
Correct Answer:
h/(√2π)
Explanation:
Orbital Angular Momentum = h/(2π) x √(l(l+1)). For p orbital, l=1. so => h/(2π) x √2 =? h/(√2π)
Related Questions: - Ethyne can be oxidised to oxalic acid by using
- The bond dissociation energies of H₂, Cl₂ and HCl are 104, 58, and 103
- An isocyanide on hydrolysis gives
- If an electron has spin quantum number of +1/2 and a magnetic quantum number
- Two chemicals having same chemical formula but different arrangement of atoms
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ethyne can be oxidised to oxalic acid by using
- The bond dissociation energies of H₂, Cl₂ and HCl are 104, 58, and 103
- An isocyanide on hydrolysis gives
- If an electron has spin quantum number of +1/2 and a magnetic quantum number
- Two chemicals having same chemical formula but different arrangement of atoms
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply