| ⇦ | 
| ⇨ |
The orbital angular momentum of a p-electron is given as :
Options
(a) h/(√2π)
(b) √3 x (h/2π)
(c) √(3/2) x h/π
(d) √6 x h/2π
Correct Answer:
h/(√2π)
Explanation:
Orbital Angular Momentum = h/(2π) x √(l(l+1)). For p orbital, l=1. so => h/(2π) x √2 =? h/(√2π)
Related Questions: - The number of acidic protons in H₃PO₃ are
- Bauxite is concentrated by
- Benzaldehyde can be prepared by the hydrolysis of
- Which of the following will show a negative deviation from Raoult’s law
- The oxidation numbers of hydrogen in KH,MgH₂ and NaH are respectively
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The number of acidic protons in H₃PO₃ are
- Bauxite is concentrated by
- Benzaldehyde can be prepared by the hydrolysis of
- Which of the following will show a negative deviation from Raoult’s law
- The oxidation numbers of hydrogen in KH,MgH₂ and NaH are respectively
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply