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The orbital angular momentum of a p-electron is given as :
Options
(a) h/(√2π)
(b) √3 x (h/2π)
(c) √(3/2) x h/π
(d) √6 x h/2π
Correct Answer:
h/(√2π)
Explanation:
Orbital Angular Momentum = h/(2π) x √(l(l+1)). For p orbital, l=1. so => h/(2π) x √2 =? h/(√2π)
Related Questions: - Which of the following corresponds to the electronic configuration 1s², 2s²,2p⁶
- Which of the following acts as an oxidising as well as reducing agent
- Boron has two stable isotopes, ¹°B(19%) and ¹¹B(81%). Average atomic weight
- The most easily hydrolysed molecule under SN1 conditions is
- Ammonia can be dried by
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following corresponds to the electronic configuration 1s², 2s²,2p⁶
- Which of the following acts as an oxidising as well as reducing agent
- Boron has two stable isotopes, ¹°B(19%) and ¹¹B(81%). Average atomic weight
- The most easily hydrolysed molecule under SN1 conditions is
- Ammonia can be dried by
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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