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The number of photons of wavelength of 540 nm emitted per second by an electric bulb of power 100 W is (given h=6×10⁻³⁴ J-s)
Options
(a) 100
(b) 1000
(c) 3×10²⁰
(d) 3×10¹⁸
Correct Answer:
3×10²⁰
Explanation:
Power = nhc / ( × t)
⇒ 100 = [n × (6 × 10⁻³⁴) × (3 × 10⁸)] / (540 × 10⁹ × 1)
⇒ n × 18 × 10⁻²⁶ / 540 × 10⁻⁹ = 100
⇒ n = 100 × 540 × 10⁻⁹ / 18 × 10⁻²⁶ = 3 x 10²⁰
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A source and an observer approach each other with same velocity 50 m/s. If the frequency
- A string in musical instrument is 50 cm long and its fundamental frequency is 800 Hz.
- In a circuit, L,C and R are connected in series with an alternating voltage source
- A coil of inductive reactance 31 Ω has a resistance of 8 Ω. It is placed in series
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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