| ⇦ |
| ⇨ |
The number of gram molecules of oxygen in 6.02 x 10²⁴ CO molecules is
Options
(a) 10 gm molecules
(b) 5 gm molecules
(c) 1 gm molecules
(d) 0.5 gm molecules
Correct Answer:
5 gm molecules
Explanation:
6.02 x 10²³ molecules of CO = 1 mole of CO
6.02 x 10²⁴ molecules of CO = 10 mole of CO
= 10 g atoms of O = 5 g molecules of O₂
Related Questions: - Which statement is incorrect
- If the equilibrium constant for reaction is K, the equilibrium constant for
- The gas molecules have r.m.s. velocity of its molecules as 1000 m/s
- In an isobaric process, the ratio of heat supplied to the system (dQ)
- Carbylamine reaction is given by
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which statement is incorrect
- If the equilibrium constant for reaction is K, the equilibrium constant for
- The gas molecules have r.m.s. velocity of its molecules as 1000 m/s
- In an isobaric process, the ratio of heat supplied to the system (dQ)
- Carbylamine reaction is given by
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply