| ⇦ | 
| ⇨ |
The normality of solution containing 31.5 g of hydrated oxalic acid (H₂C₂O₄.2H₂O) in 1250 mL of solution is
Options
(a) 0.8 N
(b) 0.2 N
(c) 0.4 N
(d) 0.1 N
Correct Answer:
0.4 N
Explanation:
Normality = Number of g.equivalents of solute/volume of solution (L).
Equivalent of mass of H₂C₂O₄.
2H₂O = 126/2 = 63.
Number of g. equivalents = 31.5/63 = 1/2 .
Normality = 1/ 2 ⨯1250⨯ 1000 = 0.4 N.
Related Questions: - Identify the molecule that has zero dipole moment
- Which of the following species is not electrophilic in nature
- Which of the following element,has the same oxidation state in all of its com.
- The change in oxidation state of sulphur when sulphur dioxide is passed
- Sodium thiosulphate is added in photography to
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Identify the molecule that has zero dipole moment
- Which of the following species is not electrophilic in nature
- Which of the following element,has the same oxidation state in all of its com.
- The change in oxidation state of sulphur when sulphur dioxide is passed
- Sodium thiosulphate is added in photography to
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply