| ⇦ | 
| ⇨ |
The normality of solution containing 31.5 g of hydrated oxalic acid (H₂C₂O₄.2H₂O) in 1250 mL of solution is
Options
(a) 0.8 N
(b) 0.2 N
(c) 0.4 N
(d) 0.1 N
Correct Answer:
0.4 N
Explanation:
Normality = Number of g.equivalents of solute/volume of solution (L).
Equivalent of mass of H₂C₂O₄.
2H₂O = 126/2 = 63.
Number of g. equivalents = 31.5/63 = 1/2 .
Normality = 1/ 2 ⨯1250⨯ 1000 = 0.4 N.
Related Questions:
- In an isobaric process,when temperature changes from T₁ to T₂, ΔS is equal to
- Atoms or ions missing from the normal lattice point creating a vacancy is due to
- Set of isoelectronic species is
- Of the following, which change will shift the reaction towards the product
- In Lassaigne’s test red colour precipitate is obtained which is due to formation
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply