| ⇦ | 
| ⇨ |
The normality of solution containing 31.5 g of hydrated oxalic acid (H₂C₂O₄.2H₂O) in 1250 mL of solution is
Options
(a) 0.8 N
(b) 0.2 N
(c) 0.4 N
(d) 0.1 N
Correct Answer:
0.4 N
Explanation:
Normality = Number of g.equivalents of solute/volume of solution (L).
Equivalent of mass of H₂C₂O₄.
2H₂O = 126/2 = 63.
Number of g. equivalents = 31.5/63 = 1/2 .
Normality = 1/ 2 ⨯1250⨯ 1000 = 0.4 N.
Related Questions:
- For the cell reactionCu²⁺ (C₁.aq) + Zn(s) = Zn²⁺(C₂.aq ) + Cu(s)
- When two atoms of chlorine combine to form one molecule of chlorine gas
- Chlorobenzene can be prepared by reacting aniline with
- At 25⁰ C , the highest osmotic pressure is exhibited by 0.1 M solution of
- Which of the following statement about the member of any one homologous series
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply