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The motion of a particle along a straight line is described by equation : x= 8 + 12t– t³ where x is in metre and t in second. The retardation of the particle when its velocity becomes zero, is :
Options
(a) 24 ms⁻²
(b) zero
(c) 6ms⁻²
(d) 12 ms⁻²
Correct Answer:
12 ms⁻²
Explanation:
x = 8 + 12t – t³ The final velocity of the particle will be zero, because it retarded.
V= 0 + 12 – 3t² = 0 ⇒ 3t² = 12 ⇒ t = 2 sec
Now the retardation a = dv/ dt = 0 – 6t
a [ t= 2] = – 12 m/s²
retardation = 12 m/s²
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 secs
- Element ²³⁴U has 92 protons and 234 nucleons in its nucleus. It decays by
- Three solids of masses m₁,m₂ and m₃ are connected with weightless string
- For the normal eye, the cornea of eye provides a converging power of 40D
- If oxygen has root mean square velocity of C m/s, then root mean square velocity of H
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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