| ⇦ | 
| ⇨ |
The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc
Options
(a) 1/2 MR²
(b) MR²
(c) 2/5 MR²
(d) 3/2 MR²
Correct Answer:
3/2 MR²
Explanation:
Moment of inertia of a uniform circular disc about an axis through its centre and perpendicular of its plane is,
Ic = (1/2) MR²
By the theorem of parallel axes,
Therefore, moment of inertia of a uniform circular disc about an axis touching the disc at its diameter and normal to the disc is I.
I = Ic + Mh² = (1/2) MR² + MR² = (3/2) MR².
Related Questions: - A comb run through one’s dry hair attracts small bits of paper. This is due to
- A body of length 1 m having cross-sectional area 0.75 m² has heat flow through it
- A mixture consists of two radioactive materials A₁ and A₂ with half lives of 20s
- Two identical capacitors are first connected in series and then in parallel.
- What is the wavelength of light for the least energetic photon emitted
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A comb run through one’s dry hair attracts small bits of paper. This is due to
- A body of length 1 m having cross-sectional area 0.75 m² has heat flow through it
- A mixture consists of two radioactive materials A₁ and A₂ with half lives of 20s
- Two identical capacitors are first connected in series and then in parallel.
- What is the wavelength of light for the least energetic photon emitted
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply