| ⇦ |
| ⇨ |
The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc
Options
(a) 1/2 MR²
(b) MR²
(c) 2/5 MR²
(d) 3/2 MR²
Correct Answer:
3/2 MR²
Explanation:
Moment of inertia of a uniform circular disc about an axis through its centre and perpendicular of its plane is,
Ic = (1/2) MR²
By the theorem of parallel axes,
Therefore, moment of inertia of a uniform circular disc about an axis touching the disc at its diameter and normal to the disc is I.
I = Ic + Mh² = (1/2) MR² + MR² = (3/2) MR².
Related Questions: - On heating a ferromagnetic substance above curie temperature
- A thin circular ring of mass M and radius R is rotating in a horizontal plane about
- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
- In Raman effect, Stoke’s lines are spectral lines having
- A speeding motorcyclist sees traffic jam ahead him. He slows down to 36 km per hour
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- On heating a ferromagnetic substance above curie temperature
- A thin circular ring of mass M and radius R is rotating in a horizontal plane about
- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
- In Raman effect, Stoke’s lines are spectral lines having
- A speeding motorcyclist sees traffic jam ahead him. He slows down to 36 km per hour
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply