| ⇦ | 
| ⇨ |
Steam at 100⁰C is passed into 20 g of water at 10°C. When water acquires a temperature of 80°C, the mass of water present will be[Take specific heat of water=1 cal g⁻¹ °C⁻¹ and latent heat of steam=540 cal g⁻¹]
Options
(a) 24 g
(b) 31.5 g
(c) 42.5 g
(d) 22.5 g
Correct Answer:
22.5 g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In a common emitter (CE) amplifier having a voltage gain G, the transistor
- Which gate can be obtained by shorting both the input terminals of a NOR gate?
- The masses of three wires of copper are in the ratio 1:3:5 and lengths
- what should be the velocity of an electron so that its momentum becomes equal
- Four point masses, each of value m, are placed at the corners of a square ABCD
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a common emitter (CE) amplifier having a voltage gain G, the transistor
- Which gate can be obtained by shorting both the input terminals of a NOR gate?
- The masses of three wires of copper are in the ratio 1:3:5 and lengths
- what should be the velocity of an electron so that its momentum becomes equal
- Four point masses, each of value m, are placed at the corners of a square ABCD
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply