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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two racing cars of masses m₁ and m₂ are moving in circles of radii
- A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
- A DC ammeter has resistance 0.1Ω and its current ranges 0-100A. If the range
- The magnetic susceptibility of a material of a rod is 299. Permeability of vacuum
- A condenser has a capacity 2 μF and is charged to a voltage of 50 V. The energy
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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