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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A transformer rated at 10 kW is used to connect a 5 kV transmission line to a 240 V
- The maximum particle velocity in a wave motion is half the wave velocity.
- A parallel plate capacitor is charged and then isolated. The effect of increasing
- If 20% of a radiactive element decays in 10 days, then amount of original material left
- The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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