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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If angular momentum of a body is increased by 200% its kinetic energy will increase
- If the nucleus ²⁷₁₃Al has nuclear radius of about 3.6 fm
- A piece of marble is projected from the earth’s surface with velocity of 50 m/s
- A spring when stretched by 2mm containing energy 4 J. If it is stretched
- The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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