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A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter nucleus is
Options
(a) A-4/4v
(b) 4v/A-4
(c) v
(d) v/4
Correct Answer:
4v/A-4
Explanation:
According to the question, zXᴬ → z-₂ Yᴬ⁻⁴ + ₂He⁴
Let the recoil speed of daughter nucleus is ʋ’. By the law of conservation of momentum, we have Initial momentum = Final momentum
0 = (A – 4)ʋ’ + 4ʋ
(A – 4) ʋ’ = -4ʋ ⇒ ʋ’ = 4ʋ / (A – 4)
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electric field in a certain region is acting radially outward and is given by E=Ar.
- A thin rod of length L and mass M is held vertically with one end on the floor
- The half-life period of a radio-active element X is same as the mean life time
- An inductor coil is connected to a 12 V battery and drawing a current 24 A. This coil
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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