| ⇦ | 
| ⇨ |
The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
Related Questions: - A particle moves a distance x in time but according to equation x=(t+5)⁻¹
- An insulated container of gas has two champers seperated by an insulating partition.
- The magnetic susceptibility is negative for
- Match the following columns about collision
- A short magnet of magnetic moment M, is placed on a straight line. The ratio
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves a distance x in time but according to equation x=(t+5)⁻¹
- An insulated container of gas has two champers seperated by an insulating partition.
- The magnetic susceptibility is negative for
- Match the following columns about collision
- A short magnet of magnetic moment M, is placed on a straight line. The ratio
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply