| ⇦ | 
| ⇨ |
The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
Related Questions: - The wavelength of kα, X-rays produced by an X-ray tube 0.76Å. The atomic number
- When a bullet of mass 10 g and speed 100 ms⁻¹ penetrates up to distance 1 cm
- Calculate the charge on equivalent capacitance of the conbination shown in figure
- A point charge is kept at the centre of a metallic insulated spherical shell. Then
- Two identical circular coils A and B are kept on a horizontal tube
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wavelength of kα, X-rays produced by an X-ray tube 0.76Å. The atomic number
- When a bullet of mass 10 g and speed 100 ms⁻¹ penetrates up to distance 1 cm
- Calculate the charge on equivalent capacitance of the conbination shown in figure
- A point charge is kept at the centre of a metallic insulated spherical shell. Then
- Two identical circular coils A and B are kept on a horizontal tube
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply