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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin rod of length L and mass M is bent at its midpoint into two halves
- A black body is at 727⁰C. It emits energy at a rate which is proportional to
- If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton
- The root mean square speed of oxygen molecule (O₂) at a certain temperature is v.
- The maximum and minimum intensities of two sources is 4:1. The ratio of amplitude is
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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