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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An aeroplane is flying horizontally with a velocity of 216 km/h at a height of 1960 m.
- A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state
- The minimum wavelength of X-rays produced in a Collidge tube operated
- In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
- Consider 3rd orbit of He⁺(helium), using non-relativistic approach, the speed
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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