⇦ | ⇨ |
The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
Related Questions: - If a charge on the body is 1nC, then how many electrons are present on the body?
- If α (current gain) of transistor is 0.98, then what is the value of β
- A particle is executing a simple harmonic motion. Its maximum acceleration
- Two point charges +2 coulomb and +10 coulomb repel each other with a force of 12 N.
- A capacitor having a capacity of 2 μF is charged to 200V and then the plates
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a charge on the body is 1nC, then how many electrons are present on the body?
- If α (current gain) of transistor is 0.98, then what is the value of β
- A particle is executing a simple harmonic motion. Its maximum acceleration
- Two point charges +2 coulomb and +10 coulomb repel each other with a force of 12 N.
- A capacitor having a capacity of 2 μF is charged to 200V and then the plates
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply