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The mean free path of electrons in a metal is 4 x 10⁻⁸ m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units of V/m
Options
(a) 5 x 10⁻¹¹
(b) 8 x 10⁻¹¹
(c) 5 x 10⁷
(d) 8 x 10⁷
Correct Answer:
5 x 10⁷
Explanation:
E = V / d = 2 / 4 x 10⁻⁸
0.5 x 10⁸ = 5 x 10⁷ Vm⁻¹
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The voltage of an a.c.supply varies with time (t) as V=120 sin 100 πt the maximum voltage
- If a proton, a deuteron and an alpha particle, on being accelerated by the same
- A bullet emerges from a barrel of length 1.2 m with a speed of 640 ms⁻¹.
- The momentum of a photon of energy 1 MeV in kg m/s will be
- When a biconvex lens of glass having refractive index 1.47 is dipped in a liquid
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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