The maximum and minimum intensities of two sources is 4:1. The ratio of amplitude is

⇦

⇨

The maximum and minimum intensities of two sources is 4:1. The ratio of amplitude is

Options

(a) 3 : 1
(b) 1 : 3
(c) 1 : √3
(d) √3 : 1

Correct Answer:

3 : 1

Explanation:

The intensity is proportional to the square of the amplitude.
Therefore if the intensities-maximum of one source and minimum of the other is taken, then the answer is different. But from the answer we presume that the light from two sources of different amplitudes are superposed. In that case,
Iₘₐₓ / Iₘᵢₙ = [A₁+A₂ / A₁-A₂]²
⇒ 4/1 = [A₁+A₂ / A₁-A₂]²
2/1 = [A₁+A₂ / A₁-A₂]
Using componendo and dividendo
2+1 / 2-1 = A₁/A₂ ⇒ A₁/A₂ = 3/1 = 3 : 1

Related Questions:

1. An electric dipole of moment p is lying along a uniform electric field E. The work
2. A cockroach is moving with a velocity v in anticlockwise direction on the rim
3. If the pressure of gas is increased from 1.01×10⁵ Pa to 1.165×10⁵ Pa and volume
4. Astigmatism is corrected by using
5. The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet

Topics: Waves (80)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends