| ⇦ | 
| ⇨ |
The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ⁷₃ Li nucleus is nearly
Options
(a) 46 MeV
(b) 5.6 MeV
(c) 3.9 MeV
(d) 23 MeV
Correct Answer:
5.6 MeV
Explanation:
B.E. = 0.042 x 931 = 42 MeV
Number of nucleons in ⁷₃Li is 7.
B.E. / nucleon = 42/7 = 6 MeV
app. 5.6 MeV
Related Questions: - The acceleration due to gravity near the surface of a planet of radius R and density d
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- A long horizontal rod has a bead which can slide long its length
- In the diffraction pattern of a single slit
- A uniform force of (3i + j) newton acfs on a particle of mass 2kg
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The acceleration due to gravity near the surface of a planet of radius R and density d
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- A long horizontal rod has a bead which can slide long its length
- In the diffraction pattern of a single slit
- A uniform force of (3i + j) newton acfs on a particle of mass 2kg
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply