| ⇦ | 
| ⇨ |
The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ⁷₃ Li nucleus is nearly
Options
(a) 46 MeV
(b) 5.6 MeV
(c) 3.9 MeV
(d) 23 MeV
Correct Answer:
5.6 MeV
Explanation:
B.E. = 0.042 x 931 = 42 MeV
Number of nucleons in ⁷₃Li is 7.
B.E. / nucleon = 42/7 = 6 MeV
app. 5.6 MeV
Related Questions: - The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- A liquid wets a solid completely. The meniscus of the liquid in a sufficiently long
- Frequency of stretched string will increase by
- When a mass M is attached to the spring of force constant k,
- Order of e/m ratio of proton, α-particle and electron is
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
- A liquid wets a solid completely. The meniscus of the liquid in a sufficiently long
- Frequency of stretched string will increase by
- When a mass M is attached to the spring of force constant k,
- Order of e/m ratio of proton, α-particle and electron is
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply