| ⇦ |
| ⇨ |
The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons. The binding energy per nucleon of ⁷₃ Li nucleus is nearly
Options
(a) 46 MeV
(b) 5.6 MeV
(c) 3.9 MeV
(d) 23 MeV
Correct Answer:
5.6 MeV
Explanation:
B.E. = 0.042 x 931 = 42 MeV
Number of nucleons in ⁷₃Li is 7.
B.E. / nucleon = 42/7 = 6 MeV
app. 5.6 MeV
Related Questions: - The necessary condition in making of a junction transistor
- A black body is heated from 27° C to 127° C. The ratio of their energies of radiations
- In some region, gravitational field is zero. The gravitational potential
- Find out the angle of projection, if range is 4 times of maximum height
- Two sources P and Q produce notes of frequency 660 Hz each.
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The necessary condition in making of a junction transistor
- A black body is heated from 27° C to 127° C. The ratio of their energies of radiations
- In some region, gravitational field is zero. The gravitational potential
- Find out the angle of projection, if range is 4 times of maximum height
- Two sources P and Q produce notes of frequency 660 Hz each.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply