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The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T. A proton is shot into the field with velocity v=(2×10⁵i ̂ + 4×10⁵ j ̂ ) m/s. The proton follows a helical path in the field. The distance moved by proton in the x-direction during the period of one revolution in the yz- plane will be (mss of proton=1.67×10⁻²⁷ kg)
Options
(a) 0.053 m
(b) 0.136 m
(c) 0.157 m
(d) 0.236 m
Correct Answer:
0.157 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Given A=4i+6j and B=2i+3j. Which of the following is correct?
- When a light beam of frequency v is incident on a metal surface,
- A bullet of mass 0.05 kg moving with a speed of 80 m/s enters a wooden
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Given A=4i+6j and B=2i+3j. Which of the following is correct?
- When a light beam of frequency v is incident on a metal surface,
- A bullet of mass 0.05 kg moving with a speed of 80 m/s enters a wooden
- A block of mass m is moving on a wedge with the acceleration aᵒ
- If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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