⇦ | ⇨ |
The magnetic field in a certain region of space is given by B =8.35×10⁻² Î T. A proton is shot into the field with velocity v=(2×10⁵i ̂ + 4×10⁵ j ̂ ) m/s. The proton follows a helical path in the field. The distance moved by proton in the x-direction during the period of one revolution in the yz- plane will be (mss of proton=1.67×10⁻²⁷ kg)
Options
(a) 0.053 m
(b) 0.136 m
(c) 0.157 m
(d) 0.236 m
Correct Answer:
0.157 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A Carnot engine takes heat from a reservoir at 627⁰C and rejects heat
- A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery
- The total energy of a simple harmonic oscillator is proportional to
- In a ionised gas,the mobile charge carriers are
- A single slit Fraunhogger diffraction pattern is formed with white light.
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A Carnot engine takes heat from a reservoir at 627⁰C and rejects heat
- A coil of resistance 20 ohm and inductance 5H is connected with a 100V battery
- The total energy of a simple harmonic oscillator is proportional to
- In a ionised gas,the mobile charge carriers are
- A single slit Fraunhogger diffraction pattern is formed with white light.
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply