| ⇦ |
| ⇨ |
The total energy of electron in the ground state of hydrogen atom is -13.6 eV. The kinetic energy of an electron in the first excited state is
Options
(a) 6.8 eV
(b) 13.6 eV
(c) 1.7 eV
(d) 3.4 eV
Correct Answer:
3.4 eV
Explanation:
Energy in the first excited state
= – 13.6 / n² = – 13.6 / 2² = – 3.4 eV
But K.E. = – (Total energy) = +3.4 eV.
Related Questions: - A projectile is fired at 30°. Neglecting friction, the change in kinetic energy when
- The weight of a body on surface of earth is 12.6 N. When it is raised to a height
- Two balls are dropped from heights h and 2h respectively. The ratio of times
- The wavelength of light emitted from second orbit to first orbit in a hydrogen atom is
- To draw the maximum current from a combination of cells, how should be the cells
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A projectile is fired at 30°. Neglecting friction, the change in kinetic energy when
- The weight of a body on surface of earth is 12.6 N. When it is raised to a height
- Two balls are dropped from heights h and 2h respectively. The ratio of times
- The wavelength of light emitted from second orbit to first orbit in a hydrogen atom is
- To draw the maximum current from a combination of cells, how should be the cells
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply