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The ionization energy of Li⁺⁺ is equal to
Options
(a) 9hcR
(b) 6hcR
(c) 2hcR
(d) hcR
Correct Answer:
9hcR
Explanation:
Ionisation energy of Li⁺⁺ = 9hcR
Ionisation energy = RchZ² = Rhc(3)² = 9hcR [as Z = 3 for Li⁺⁺]
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