| ⇦ |
| ⇨ |
The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released when an electron jumps from the first excited state (n=2) to the ground state of hydrogen atom is
Options
(a) 3.4 eV
(b) 4.53 eV
(c) 10.2 eV
(d) 13.6 eV
Correct Answer:
10.2 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- A missile is fired for maximum range with an initial velocity of 20 m/s
- A L-C-R circuit with L=1.00 mH, C=10μF and R=50Ω, is driven with 5 V AC voltage.
- When one of the slits of Young’s experiment is covered with a transport sheet
- Nuclear fission is not found in
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- A missile is fired for maximum range with an initial velocity of 20 m/s
- A L-C-R circuit with L=1.00 mH, C=10μF and R=50Ω, is driven with 5 V AC voltage.
- When one of the slits of Young’s experiment is covered with a transport sheet
- Nuclear fission is not found in
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply