| ⇦ | 
| ⇨ |
The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released when an electron jumps from the first excited state (n=2) to the ground state of hydrogen atom is
Options
(a) 3.4 eV
(b) 4.53 eV
(c) 10.2 eV
(d) 13.6 eV
Correct Answer:
10.2 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
- The value of Poisson’s ratio lies between
- A thin circular ring of mass M and radius R is rotating in a horizontal plane about
- A light emitting diode(LED) has a voltage drop of 2 volt across it
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply