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The internal energy change in a system that has absorbed 2 kcals of heat and done 500J of work is:
Options
(a) 6400 J
(b) 5400 J
(c) 7900 J
(d) 8900 J
Correct Answer:
7900 J
Explanation:
According to first law of thermodynamics Q = ∆U + W
∆U = Q – W = 2 x 4.2 x 1000 – 500 = 8400 – 500 = 7900 J
Related Questions: - At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure
- The ratio of longest wavelength corresponding to Lyman and Blamer series
- A car moving with a speed of 50 kmh⁻¹ can be stopped by brakes after at least 6 m
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure
- The ratio of longest wavelength corresponding to Lyman and Blamer series
- A car moving with a speed of 50 kmh⁻¹ can be stopped by brakes after at least 6 m
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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