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The internal energy change in a system that has absorbed 2 kcals of heat and done 500J of work is:
Options
(a) 6400 J
(b) 5400 J
(c) 7900 J
(d) 8900 J
Correct Answer:
7900 J
Explanation:
According to first law of thermodynamics Q = ∆U + W
∆U = Q – W = 2 x 4.2 x 1000 – 500 = 8400 – 500 = 7900 J
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electric motor runs on DC source of emf 200 V and draws a current of 10 A.
- The number of NAND gates required to form an AND gate is
- One-fourth length of a spring of force constant K is cut away. The force constant
- The time of reverberation of a room A is one second. What will be the time (in seconds)
- The resistance in the two arms of the meter bridge are 5Ω and RΩ, respectively
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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