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The internal energy change in a system that has absorbed 2 kcals of heat and done 500J of work is:
Options
(a) 6400 J
(b) 5400 J
(c) 7900 J
(d) 8900 J
Correct Answer:
7900 J
Explanation:
According to first law of thermodynamics Q = ∆U + W
∆U = Q – W = 2 x 4.2 x 1000 – 500 = 8400 – 500 = 7900 J
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two radiations of photons energies 1 eV and 2.5 eV, successively
- If radius of earth’s orbit is made 1/4, the duration of a year will become
- A sphere of 4cm radius is suspended with in a hollow sphere of 6cm radius. If the inner
- A gas of monoatomic hydrogen is bombarded with a stream of electrons
- A short bar magnet of magnetic moment 0.4 JT⁻¹ is placed in a uniform magnetic field
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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