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The internal energy change in a system that has absorbed 2 kcals of heat and done 500J of work is:
Options
(a) 6400 J
(b) 5400 J
(c) 7900 J
(d) 8900 J
Correct Answer:
7900 J
Explanation:
According to first law of thermodynamics Q = ∆U + W
∆U = Q – W = 2 x 4.2 x 1000 – 500 = 8400 – 500 = 7900 J
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two particles A and B having equal charges +6C, after being accelerated
- The component of vector A=2i+3j along the vector i+j is
- Ratio of the radii of the nuclei with mass numbers 8 and 27 would be
- Copper has face centered cubic (fcc) lattice with interatomic spacing equal to 2.54Å.
- The near point and far point of a person are 40 cm and 250 cm, respectively.
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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