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The internal energy change in a system that has absorbed 2 kcals of heat and done 500J of work is:
Options
(a) 6400 J
(b) 5400 J
(c) 7900 J
(d) 8900 J
Correct Answer:
7900 J
Explanation:
According to first law of thermodynamics Q = ∆U + W
∆U = Q – W = 2 x 4.2 x 1000 – 500 = 8400 – 500 = 7900 J
Related Questions: - A particle moves along a circle of radius 20/π m with constant tangential acceleration
- A ray of light is incident on a transparent glass slab of refractive index 1.62
- A thermodynamic system undergoes cyclic process ABCDA as shown in figure
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves along a circle of radius 20/π m with constant tangential acceleration
- A ray of light is incident on a transparent glass slab of refractive index 1.62
- A thermodynamic system undergoes cyclic process ABCDA as shown in figure
- A potentiometer circuit has been set up for finding the internal resistance of a given
- At place on earth, the vertical component of earth’s magnetic field is √3 times
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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