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The internal energy change in a system that has absorbed 2 kcals of heat and done 500J of work is:
Options
(a) 6400 J
(b) 5400 J
(c) 7900 J
(d) 8900 J
Correct Answer:
7900 J
Explanation:
According to first law of thermodynamics Q = ∆U + W
∆U = Q – W = 2 x 4.2 x 1000 – 500 = 8400 – 500 = 7900 J
Related Questions: - A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
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- Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
- The drift velocity of the electrons in a copper wire of length 2 m under
- Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
- The average power dissipated in AC circuit is 2 W. If a current flowing through
- An electric kettle has two heating elements. One brings it to boil in ten minutes
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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