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The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?
Options
(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀
Correct Answer:
I₀/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The phase difference between the instantaneous velocity and acceleration of a particle
- If radius of earth’s orbit is made 1/4, the duration of a year will become
- According to photon theory of light which of the following physical quantities,
- The resistances of the four arms P,Q,R and S in a Wheatstone’s bridge
- A wire having resistance 12Ω is bent in the form of an equilateral triangle.
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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