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The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?
Options
(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀
Correct Answer:
I₀/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of the weight of a man in a stationary lift and when it is moving downwards
- Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen
- A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km
- Two coherent monochromatic beams of intensities I and 4I respectively, are superposed.
- If both the resistance and the inductance in an LR AC series circuit are doubled
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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