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The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?
Options
(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀
Correct Answer:
I₀/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At place on earth, the vertical component of earth’s magnetic field is √3 times
- The transition from the state 3 n = 3 to n = 1 in a hydrogen like atom results
- An artificial satellite is revolving round the earth in a circular orbit. Its velocity
- A boy standing at top of a tower of 20 m height drops a stone
- The work function for metals A,B abd C are respectively 1.92 eV,2.0 eV and 5 eV.
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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