The intensity at the maximum in a Young’s double slit experiment is I₀.

The Intensity At The Maximum In A Youngs Double Slit Physics Question

The intensity at the maximum in a Young’s double slit experiment is I₀. Distance between two slits is d=5λ, where λ is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance, D= 10 d?

Options

(a) I₀/4
(b) 3/4 I₀
(c) I₀/2
(d) I₀

Correct Answer:

I₀/2

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. A particle moving in a straight line covers half the distance with speed of 3 m/s
  2. The numebr 0 (zero) is required for
  3. Reactance of a capacitor of capacitance C µF for A.C freqency (400 / π) Hz is 25 ohm
  4. A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature
  5. A silver wire of radius 0.1 cm carries a current of 2A. If the charge density in silver

Topics: Wave Optics (101)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*