| ⇦ |
| ⇨ |
The induced emf in a coil of 10 H inductance in which current varies from 9 A to 4 A in 0.2 s is
Options
(a) 200 V
(b) 250 V
(c) 300 V
(d) 350 V
Correct Answer:
250 V
Explanation:
Induced emf, e = -L (di / dt)
Given, L = 10 H, Δi = 9 – 4 = 5 A,
dt = 0.2 s
emf, e = 10 × (5 / 0.2) = 250 V
Related Questions: - Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radius
- Two identical cells of the same e.m.f. and same internal resistance
- On the horizontal surface of a truck a block of mass 1 kg is placed (µ=0.6) and truck
- The charges Q, +q, and +q are placed at the vartices of an equilateral
- If the highest modulating frequency of the wave is 5 kHz, the number
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radius
- Two identical cells of the same e.m.f. and same internal resistance
- On the horizontal surface of a truck a block of mass 1 kg is placed (µ=0.6) and truck
- The charges Q, +q, and +q are placed at the vartices of an equilateral
- If the highest modulating frequency of the wave is 5 kHz, the number
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply