| ⇦ | 
| ⇨ |
The increasing order of the density of alkali metals
Options
(a) Li < K < Na < Rb < Cs
(b) Li < Na < K < Rb < Cs
(c) Cs < Rb < Na < K < Li
(d) Cs < Rb < K < Na < Li
Correct Answer:
Li < K < Na < Rb < Cs
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The aqueous solution of which of the following salt will have the lowest pH
- Identify the molecule that has zero dipole moment
- The two electrons in K-subshell will differ in
- Standard reduction potential for Al³⁺/Al , Fe²/Fe, Br/Br are ₋1.66V, ₋0.45V, 1.09V
- The physical adsorption of gases on the solid surface is due to
Topics: S and Some P Block Elements
(157)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The aqueous solution of which of the following salt will have the lowest pH
- Identify the molecule that has zero dipole moment
- The two electrons in K-subshell will differ in
- Standard reduction potential for Al³⁺/Al , Fe²/Fe, Br/Br are ₋1.66V, ₋0.45V, 1.09V
- The physical adsorption of gases on the solid surface is due to
Topics: S and Some P Block Elements (157)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Li se K me K ka volume increase hota hai. Volume increase hone se
K ki density Na se bhi kam ho jati hai ( density =mass \ volume) . For this reason Li < K < Na < Rb < Cs.