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The horizontal range of a projectile is 4√3 times the maximum height achieved by it. The angle of projection is
Options
(a) 30⁰
(b) 45⁰
(c) 60⁰
(d) 90⁰
Correct Answer:
30⁰
Explanation:
u²sin 2θ/g = 4√3 x (u²sin 2θ/g ) ⇒ tan θ = 1/√3 .·. θ = 30°
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
- The Priniple of LASER action involves
- In the Bohr’s model of hydrogen atom, the ratio of the kinetic energy to the total
- A body of mass M hits normally a rigid wall with velocity V and bounces back
- Two cells, having the same e.m.f. are connected in series through an external resistance
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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