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The horizontal range of a projectile is 4√3 times the maximum height achieved by it. The angle of projection is
Options
(a) 30⁰
(b) 45⁰
(c) 60⁰
(d) 90⁰
Correct Answer:
30⁰
Explanation:
u²sin 2θ/g = 4√3 x (u²sin 2θ/g ) ⇒ tan θ = 1/√3 .·. θ = 30°
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Topics: Motion in Plane
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The slope of the graph showing the variation of potential difference V on X-axis
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- The average power dissipated in AC circuit is 2 W. If a current flowing through
- Calculate the charge on equivalent capacitance of the conbination shown in figure
- An engine pumps water continuously through a hose. Water leaves the hose
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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