The horizontal range of a projectile is 4√3 times the maximum height achieved

⇦

⇨

The horizontal range of a projectile is 4√3 times the maximum height achieved by it. The angle of projection is

Options

(a) 30⁰
(b) 45⁰
(c) 60⁰
(d) 90⁰

Correct Answer:

30⁰

Explanation:

u²sin 2θ/g = 4√3 x (u²sin 2θ/g ) ⇒ tan θ = 1/√3 .·. θ = 30°

Related Questions:

1. If the angular momentum of any rotating body increase by 200 % , then the increase
2. In the diagram shown in figure, match the following about weight
3. When npn transistor is used as an amplifier
4. In the diffraction pattern of a single slit
5. An atom bomb weighing 1 kg explodes releasing 9×10¹³ J of energy.

Topics: Motion in Plane (93)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends