| ⇦ | 
| ⇨ |
The horizontal range and maximum height attained by a projectile are R and H,respectively.If a constant horizontal acceleration a=g/4 is imparted to the projectile due to wind,then it’s horizontal range and maximum height will be
Options
(a) (R+H),H/2
(b) (R+H/2),2H
(c) (R+2H),H
(d) (R+H),H
Correct Answer:
(R+H),H
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- A mixture consists of two radioactive materials A₁ and A₂ with half lives of 20s
- Frequency of stretched string will increase by
- A bar magnet of moment of inertia I is vibrated in a magnetic field of induction
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- A mixture consists of two radioactive materials A₁ and A₂ with half lives of 20s
- Frequency of stretched string will increase by
- A bar magnet of moment of inertia I is vibrated in a magnetic field of induction
- A voltmeter of range 2 V and resistance 300Ω cannot be converted into ammeter
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply