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The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T and the dip is tan⁻¹ (4/3). A metal rod of length 0.25m is placed in N-S direction and is moved at a constant speed of 10 cms⁻¹ towards the east. The emf induced in the rod will be
Options
(a) 1μV
(b) 5μV
(c) 7μV
(d) 10μV
Correct Answer:
10μV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The Priniple of LASER action involves
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The Priniple of LASER action involves
- The horizontal and vertical components of earth’s magnetic field at a place
- In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
- When ₉₀Th²²⁸ transforms to ₈₃Bi²¹², the number of emitted α and β particles
- The mass number of nucleus is always
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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