| ⇦ | 
| ⇨ |
The horizontal and vertical components of earth’s magnetic field at a place are 0.3 G and 0.52 G. The earth’s magnetic field and the angle of dip are
Options
(a) 0.3 G and δ=30⁰
(b) 0.4 G and δ=40⁰
(c) 0.5 G and δ=50⁰
(d) 0.6 G and δ=60⁰
Correct Answer:
0.6 G and δ=60⁰
Explanation:
As, Bᴇ = √(Bʜ² + Bv²) and tan δ = Bv / Bʜ
Given, Bʜ = 0.3 G, Bv = 0.52 G
Bᴇ = √[(0.3)² + (0.52)²] = √0.36 = 0.6 G and δ = tan⁻¹ (Bv / Bʜ) = tan⁻¹ (0.52 / 0.3) = 60°
Related Questions:
- The ratio of speed of an electron in ground state in Bohr’s first orbit of hydrogen atom
- A man weighing 60 kg climbs a staircase carrying a 20 kg load on his hand
- A black body at 227⁰C radiates heat at the rate of 7cals/cm²s. At a temperature
- The force of repulsion between two electrons at a certain distance is F.
- If a charge on the body is 1nC, then how many electrons are present on the body?
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply