| ⇦ | 
| ⇨ |
The height at which the weight of a body becomes 1/16 th, its weight on the surface of earth (radius R), is
Options
(a) 5 R
(b) 15 R
(c) 3 R
(d) 4 R
Correct Answer:
3 R
Explanation:
Let at h height, the weight of a body becomes 1/16th of its weight on the surface.
Wh = 16 Ws g’ = GM/(Re+h)²
Similarly, g = GM/Re²
Now, g’/g = Re²/(Re+h)²
⇒ g’=g(1+h/R)⁻²
⇒ Wh = 16 Ws
⇒ g’ = g/16 g’
= 16g(1+h/R)⁻² 1/16
= (1+h/R)⁻²
⇒ 4 = 1+h/R
⇒ h = 3 R
Related Questions: - The phase difference between two points seperated by 0.8 m in a wave of frequency
- The current gain of a transistor in common base configuration is 0.96.
- Electrons used in an electron microscope are accelerated by a voltage of 25 kV
- The point of suspension λ of a simple pendulum with normal time period T₁ is moving
- Initial pressure and volume of a gas are P and 800cc. If the final volume is 100cc
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The phase difference between two points seperated by 0.8 m in a wave of frequency
- The current gain of a transistor in common base configuration is 0.96.
- Electrons used in an electron microscope are accelerated by a voltage of 25 kV
- The point of suspension λ of a simple pendulum with normal time period T₁ is moving
- Initial pressure and volume of a gas are P and 800cc. If the final volume is 100cc
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply