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The Formation of the oxide ion, O²⁻ from oxygen atom requires first an exothermic and then an endothermic step as shown below:
O(g) + e⁻ → O⁻(g) ; Δf H° = -141 kJ mol⁻¹
O⁻(g) + e⁻ → O²⁻(g) ; Δf H° = +780 kJ mol⁻¹
Thus, process of formation of O²⁻ in gas phase is unfavourable even though O²⁻ is isoelectronic with neon. It is due to the fact that,
Options
(a) O⁻ ion has comparatively smaller size than oxygen atom
(b) oxygen is more electronegative
(c) addition of electron in oxygen results in larger size of the ion
(d) electron repulsion outweighs the stability gained by achieving noble gas configuration
Correct Answer:
electron repulsion outweighs the stability gained by achieving noble gas configuration
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Primary alcohols can be prepared by the reaction of RMgx with
- In laboratory burners , we use
- When alkyl halide is heated, with dry Ag₂O, it produces
- A mixture of potassium chlorate, oxalic acid and sulphuric acid is heated.
- The hydrolysis of 2-bromo-3-methylbutane by SN1mechanism gives mainly
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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