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The escape velocity of a body from earth’s surface is Ve. The escape velocity of the same body from a height equal to 7R from earth’s surface will be
Options
(a) Ve/√2
(b) Ve/2
(c) Ve/2√2
(d) Ve/4
Correct Answer:
Ve/2√2
Explanation:
Escape velocity of body from the earth’s surface is Ve=√2gR
Escape velocity of a same body at a height h from the earth’s surface is,Ve’=√2gR²/R+h
Given h=7R
Ve’=√2gR²/R+7R ⇒ √2gR²/R[1+7]
=√2gR/8 ⇒ 1/2√2 √2gR
=1/2√2 Ve.
Related Questions: - A hemispherical bowl of radius R is rotating about its axis of symmetry
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- In communication with help of antenna if height is doubled then the range
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- A small rod of bismuth is suspended freely between the poles of a strong electromagnet.
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A hemispherical bowl of radius R is rotating about its axis of symmetry
- A wire of length 1 m is moving at a speed of 2 ms⁻¹ perpendicular to its length
- In communication with help of antenna if height is doubled then the range
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- A small rod of bismuth is suspended freely between the poles of a strong electromagnet.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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