| ⇦ | 
| ⇨ |
The escape velocity from the earth is Ve. The escape velocity from a planet whose radius is 4 times and density is 9 times that of earth is
Options
(a) 36 Ve
(b) 12 Ve
(c) 6 Ve
(d) 20 Ve
Correct Answer:
12 Ve
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- If a magnet is suspended at an angle 30⁰ to the magnetic meridian, the dip needle
- In the equation y=asin(?t+kx),the dimensionals formula of ? is
- The distance of the moon form the earth is 3.8×10⁵ km. Supposing that the eye
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- The mass number of nucleus is always
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply