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The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is
Options
(a) ε₀E² Ad
(b) 1/2 ε₀E² Ad
(c) 1/2 ε₀E²/ Ad
(d) ε₀E² /Ad
Correct Answer:
1/2 ε₀E²/ Ad
Explanation:
The energy required to charge a parallel plate condenser is given by U = 1/2 CV²
As C =ε₀ A / d and V = E.d
U = 1/2ε₀ A / d . E²d²
= 1/2ε₀ E² Ad
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Topics: Electrostatics
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A certain metallic surface is illuminated with monochromatic light of wavelength
- SI unit of magnetic dipole moment is
- A proton carrying 1 MeV kinetic energy is moving in a circular path of radius
- A Gaussian surface in the cylinder of cross-section πa² and length L is immersed
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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