| ⇦ |
| ⇨ |
The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is
Options
(a) ε₀E² Ad
(b) 1/2 ε₀E² Ad
(c) 1/2 ε₀E²/ Ad
(d) ε₀E² /Ad
Correct Answer:
1/2 ε₀E²/ Ad
Explanation:
The energy required to charge a parallel plate condenser is given by U = 1/2 CV²
As C =ε₀ A / d and V = E.d
U = 1/2ε₀ A / d . E²d²
= 1/2ε₀ E² Ad
Related Questions: - In which of the following systems will the radius of the first orbit (n=1) be minimum?
- The magnetic susceptibility is negative for
- The resistances of the four arms P,Q,R and S in a Wheatstone’s bridge
- The additional energy that should be given to an electron to reduce its de-Broglie
- For CE transistor amplifier, the audio signal voltage across the collector resistance
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In which of the following systems will the radius of the first orbit (n=1) be minimum?
- The magnetic susceptibility is negative for
- The resistances of the four arms P,Q,R and S in a Wheatstone’s bridge
- The additional energy that should be given to an electron to reduce its de-Broglie
- For CE transistor amplifier, the audio signal voltage across the collector resistance
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply