| ⇦ |
| ⇨ |
The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is
Options
(a) ε₀E² Ad
(b) 1/2 ε₀E² Ad
(c) 1/2 ε₀E²/ Ad
(d) ε₀E² /Ad
Correct Answer:
1/2 ε₀E²/ Ad
Explanation:
The energy required to charge a parallel plate condenser is given by U = 1/2 CV²
As C =ε₀ A / d and V = E.d
U = 1/2ε₀ A / d . E²d²
= 1/2ε₀ E² Ad
Related Questions: - Consider the following two statements about Kirchhoff’s law
- A boy standing at top of a tower of 20 m height drops a stone
- The induced emf in a coil of 10 H inductance in which current varies
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
- A bullet of mass 0.05 kg moving with a speed of 80 m/s enters a wooden
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Consider the following two statements about Kirchhoff’s law
- A boy standing at top of a tower of 20 m height drops a stone
- The induced emf in a coil of 10 H inductance in which current varies
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
- A bullet of mass 0.05 kg moving with a speed of 80 m/s enters a wooden
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply