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The energy required to charge a parallel plate condenser of plate separation d and plate area of cross-section A such that the uniform electric field between the plates is E, is
Options
(a) ε₀E² Ad
(b) 1/2 ε₀E² Ad
(c) 1/2 ε₀E²/ Ad
(d) ε₀E² /Ad
Correct Answer:
1/2 ε₀E²/ Ad
Explanation:
The energy required to charge a parallel plate condenser is given by U = 1/2 CV²
As C =ε₀ A / d and V = E.d
U = 1/2ε₀ A / d . E²d²
= 1/2ε₀ E² Ad
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- On heating a ferromagnetic substance above curie temperature
- In the Bohr’s model of hydrogen atom, the ratio of the kinetic energy to the total
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- For a normal eye, the cornea of eye provides a converging power 40 D and the least
- The thermo e.m.f. E in volts of a certain thermocouple is found to vary
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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