| ⇦ | 
| ⇨ |
The energy of a hydrogen atom in the ground state is -13.6 eV. The energy of a He⁺ ion in the first excited state will be
Options
(a) – 13.6 eV
(b) – 27.7 eV
(c) – 54.4 eV
(d) – 6.8 eV
Correct Answer:
– 13.6 eV
Explanation:
energy of a H-like atom in its nth state is given by
E = – Z² x 13.6 / n² eV
For, first excited state of He⁺, n= 2, Z= 2
Eₕₑ⁺ = – 4/2² x 13.6 = – 13.6 eV
Related Questions: - The ratio of amplitude of magnetic field to the amplitude of electric field for
- In Young’s experiment, the third bright band for light of wavelength 6000Å
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
- If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton
- A plank with a box on it at one end is gradually raised about the other end.
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of amplitude of magnetic field to the amplitude of electric field for
- In Young’s experiment, the third bright band for light of wavelength 6000Å
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
- If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton
- A plank with a box on it at one end is gradually raised about the other end.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply