⇦ | ⇨ |
The energy of a hydrogen atom in the ground state is -13.6 eV. The energy of a He⁺ ion in the first excited state will be
Options
(a) – 13.6 eV
(b) – 27.7 eV
(c) – 54.4 eV
(d) – 6.8 eV
Correct Answer:
– 13.6 eV
Explanation:
energy of a H-like atom in its nth state is given by
E = – Z² x 13.6 / n² eV
For, first excited state of He⁺, n= 2, Z= 2
Eₕₑ⁺ = – 4/2² x 13.6 = – 13.6 eV
Related Questions: - A solenoid has length 0.4 cm, radius 1 cm and 400 turns of wire. If a current
- The bandgap in Germanium and silicon, in eV, are respectively
- A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity
- The original temperature of a black body is 727⁰C. The temperature at which this black
- In forward biasing of the p-n junction
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A solenoid has length 0.4 cm, radius 1 cm and 400 turns of wire. If a current
- The bandgap in Germanium and silicon, in eV, are respectively
- A rod of 10 cm length is moving perpendicular to uniform magntic field of intensity
- The original temperature of a black body is 727⁰C. The temperature at which this black
- In forward biasing of the p-n junction
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply