| ⇦ | 
| ⇨ |
Thin uniform rod of length L, cross-sectional area A and density ρ is rotated about an axis passing through centre and perpendicular to its length with angular velocity ?. What will be its rotational energy?
Options
(a) ρAL³?ￂﾲ/24
(b) ρAL²?ￂﾲ/12
(c) ρAL³?ￂﾲ/12
(d) ρA²L?ￂﾲ/24
Correct Answer:
ρAL³?ￂﾲ/24
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The oscillation of a body on a smooth horizontal surface is represented by the equation
- If vectors A=cos wti + sin wtj and B= cos wt/2 i + sin wt/2 j are functions of time,
- The intensity of magnetisation of a bar magnet is 5×10⁴ Am⁻¹. The magnetic length
- An ideal black body is equivalent to
- Electron in hydrogen atom first jumps from third excited state to second excited
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The oscillation of a body on a smooth horizontal surface is represented by the equation
- If vectors A=cos wti + sin wtj and B= cos wt/2 i + sin wt/2 j are functions of time,
- The intensity of magnetisation of a bar magnet is 5×10⁴ Am⁻¹. The magnetic length
- An ideal black body is equivalent to
- Electron in hydrogen atom first jumps from third excited state to second excited
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply