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The electric potential at the surface of an atomic nucleus (z=50) of radius 9.0×10⁻¹³ cm is
Options
(a) 80 volt
(b) 8×10⁶ volt
(c) 9 volt
(d) 9×10⁵ volt
Correct Answer:
8×10⁶ volt
Explanation:
V = (1 / 4πε₀). q/r
= [9 × 10⁹ × 50 × 1.6 × 10⁻¹⁹] / 9 × 10⁻¹⁵
= 8 × 10⁶ volt
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