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The electric field part of an electromagnetic wave in a medium is represented by Ex = 0
Ey = 2.5 (N / C) cos [(2π x 10⁶ rad/m) t – (π x 10⁻² rad/s) x ];
Ez = 0. The wave is:
Options
(a) moving along x direction with frequency 10⁶ Hz and wavelength 100 m.
(b) moving along x direction with frequency 10⁶ Hz and wave length 200 m.
(c) moving along -x direction with frequency 10⁶ Hz and wave length 200 m.
(d) moving along y direction with frequency 2π x 10⁶ Hz and wave length 200 m.
Correct Answer:
moving along x direction with frequency 10⁶ Hz and wave length 200 m.
Explanation:
Comparing with the equation of wave,
Ey = E₀ cos (ωt – kx)
ω = 2πf = 2π x 10⁶
Therefore, f = 10⁶ Hz
2π / λ = k = π x 10⁻² m⁻¹, λ = 200 m
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A current I flows along the length of an infinitely long, straight, thin walled pipe.
- Young’s modulus of the material of a wire is 18×10¹¹ dyne cm⁻².its value in SI is
- The young’s modulus of steel is twice that of brass. Two wires of same length
- The energy released by the fission of one uranium atom is 200 MeV.
- In a Rutherford scattering experiment when a projectile of charge Z₁ and mass M₁
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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